forked from 1b-agent/fieldcraft-upstream
verification: implicit plasticity oracle cases and documentation
Four cases, each against its closed form: uniaxial tension of a J2 cube to a logarithmic strain of 0.2 (Kirchhoff stress exact; 0.13 % from the explicit solver's hypoelastic Cauchy stress, the elastic volume change between the two laws), the Bauschinger effect of linear kinematic hardening on a load path back to zero strain (exact), Hill's elastic-perfectly plastic thick cylinder (bore displacement at a plastic radius of 1.5a within 0.009 %, collapse pressure within 2e-8; the pending case is now active) and a cantilever's plastic collapse, converged 3.1 % above beam theory's hinge, the bound a continuum exceeds. docs/fem.md, the literature, ROADMAP (M15), parity and the oracle page follow. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_01NmAttHhUZTokgPeEJia8sm
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# Bauschinger effect of linear kinematic hardening
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One hex8 cube (E = 200000, ν = 0.3, σ_y = 250, H = 2000, Prager's linear kinematic hardening)
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held by symmetry on three faces, its fourth face pulled to a strain of 0.01 and brought back to
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zero within one nonlinear static step without nonlinear geometry, by the load path
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[[0, 0], [0.5, 1], [1, 0]] in increments of 0.05.
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At ε_a the stress is σ_a = σ_y + E_t (ε_a − σ_y/E) = 267.327. The yield surface keeps its size
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and moves with the back stress, so unloading is elastic only until σ_a − 2σ_y and then hardens
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with E_t: back at zero strain σ = σ_a − 2σ_y − E_t (ε_a − 2σ_y/E) = −247.525. Isotropic hardening
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would yield again only at −σ_a and end at −281.835. The equivalent plastic strain accumulates
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(σ_a − σ_y)/H forward and E/(E + H)(ε_a − 2σ_y/E) in reverse, 0.0160891.
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{
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"title": "Bauschinger effect of linear kinematic hardening: tension, then back to zero strain",
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"kind": "theory",
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"source": "J2 plasticity with Prager's linear kinematic hardening in uniaxial stress (W. Prager, Ing.-Arch. 1955; Simo and Hughes, Computational Inelasticity, Springer 1998, §2.3): from σ_a = σ_y + E_t (ε_a − σ_y/E) the material unloads elastically by 2σ_y and then hardens with E_t, so at zero strain σ = σ_a − 2σ_y − E_t (ε_a − 2σ_y/E)",
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"quantities": [
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{
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"id": "residual_stress",
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"quantity": "axial stress back at zero strain after a pull to ε_a = 0.01",
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"measure": {
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"command": "solve.probe",
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"params": {
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"step": "Pull",
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"elements": [
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1
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]
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},
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"pointer": "/elements/0/stress/0/0"
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},
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"value": -247.52475247524754,
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"tolerance": {
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"relative": 1e-06
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},
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"reason": "a homogeneous small-strain state the element represents exactly, with increments that end at the load path's turn; isotropic hardening would give −281.835 (it yields again only at −σ_a)"
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},
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{
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"id": "plastic_strain",
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"quantity": "accumulated equivalent plastic strain",
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"measure": {
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"command": "solve.probe",
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"params": {
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"step": "Pull",
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"elements": [
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1
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]
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},
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"pointer": "/elements/0/plastic_strain/0"
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},
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"value": 0.016089108910891083,
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"tolerance": {
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"relative": 1e-06
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},
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"reason": "(σ_a − σ_y)/H forward plus E/(E + H) (ε_a − 2σ_y/E) in reverse"
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}
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]
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}
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{
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"note": "FieldCraft's accepted results for this case, written by `cargo xtask oracle --bless`. A result outside its band fails CI.",
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"values": {
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"plastic_strain": {
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"band": 1.6089108910891082e-11,
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"value": 0.01608910891089074
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},
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"residual_stress": {
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"band": 2.4752475247524754e-7,
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"value": -247.52475247484173
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}
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}
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}
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[
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{"command": "mesh.block", "params": {"body": "Cube", "kind": "hex8", "corners": [[0, 0, 0], [1, 0, 0], [1, 1, 0], [0, 1, 0], [0, 0, 1], [1, 0, 1], [1, 1, 1], [0, 1, 1]], "divisions": [1, 1, 1], "faces": {"6": "x0", "3": "y0", "1": "z0", "4": "x1"}}},
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{"command": "model.set.create", "params": {"name": "all", "geometry": [{"body": "Cube"}]}},
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{"command": "model.set.create", "params": {"name": "x0", "geometry": [{"body": "Cube", "face": "x0"}]}},
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{"command": "model.set.create", "params": {"name": "y0", "geometry": [{"body": "Cube", "face": "y0"}]}},
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{"command": "model.set.create", "params": {"name": "z0", "geometry": [{"body": "Cube", "face": "z0"}]}},
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{"command": "model.set.create", "params": {"name": "x1", "geometry": [{"body": "Cube", "face": "x1"}]}},
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{"command": "model.material.create", "params": {"name": "Steel", "elastic": {"type": "isotropic", "young": 200000.0, "poisson": 0.3}, "plastic": {"type": "bilinear", "yield_stress": 250.0, "hardening_modulus": 2000.0, "hardening": "kinematic"}}},
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{"command": "model.section.create", "params": {"name": "cube", "set": "all", "material": "Steel", "kind": {"type": "solid"}}},
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{"command": "model.boundary_condition.create", "params": {"name": "sx", "type": "symmetry", "target": {"set": "x0"}, "plane": "x"}},
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{"command": "model.boundary_condition.create", "params": {"name": "sy", "type": "symmetry", "target": {"set": "y0"}, "plane": "y"}},
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{"command": "model.boundary_condition.create", "params": {"name": "sz", "type": "symmetry", "target": {"set": "z0"}, "plane": "z"}},
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{"command": "model.boundary_condition.create", "params": {"name": "pull", "type": "displacement", "target": {"set": "x1"}, "values": [0.01, null, null, null, null, null]}},
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{"command": "model.step.create", "params": {"name": "Pull", "procedure": {"type": "nonlinear_static", "nonlinear_geometry": false, "initial_increment": 0.05, "max_increment": 0.05, "load_path": [[0, 0], [0.5, 1], [1, 0]]}, "boundary_conditions": ["sx", "sy", "sz", "pull"], "loads": []}},
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{"command": "solve.nonlinear", "params": {"step": "Pull"}, "id": "solve"}
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]
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