Files
OneCAD-Simulation/tests/oracle/nl-mooney-rivlin-tube/README.md
T
jyvikoandClaude Opus 5.5 d586d84859 verification: hyperelastic and thermal oracle cases and documentation
Five cases against closed forms: a Mooney-Rivlin block in Treloar's
uniaxial, equibiaxial and pure-shear modes and a Yeoh block in uniaxial
tension (the compressible energy's stresses, exact); a stretched
Mooney-Rivlin tube inflated by a follower pressure (Rivlin's incompressible
solution, 0.6 % at nu = 0.4995); free and fully held thermal expansion at a
thermal stretch of 1.2 (exact); a bar held at its ends heated past yield
(exact). docs/fem.md, the literature, ROADMAP (M15, M17), parity and the
oracle page follow.

Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01NmAttHhUZTokgPeEJia8sm
2026-10-14 07:23:06 -04:00

11 lines
773 B
Markdown
Raw Blame History

This file contains ambiguous Unicode characters
This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.
# Inflation of a stretched Mooney–Rivlin tube
The quarter tube of `nl-cylinder-inflation` (A = 10, B = 20, one unit long, 6 × 16 hybrid
hex20), now Mooney–Rivlin (E = 3, ν = 0.4995, so μ = 1.000333; C₀₁ = 0.2, C₁₀ = μ/2 − C₀₁) and
stretched axially by its end face (u_z = 0.5 at z = 1: λ_z = 1.5) while a follower pressure
p = 0.540850 inflates the bore. In plane strain (λ_z = 1) Mooney–Rivlin is neo-Hookean with
μ = 2(C₁₀ + C₀₁), since Ī₁ = Ī₂ there; the axial stretch makes the second invariant's share
count: σ_θ − σ_r = 2(λ_θ² − λ_r²)(C₁₀ + C₀₁ λ_z²). Integrated through the incompressible wall,
r² = a² + (R² − A²)/λ_z, that pressure puts the bore at a = 15 and the outer wall at
b = 20.615528.